In the binomial expansion of 〖(a-b)〗^n, n≥5, the sum of the 5th and 6th terms is zero. Then a/b equa

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In the binomial expansion `(a-b)^n, nge5` the sum of 5th and 6th terms is zero. Then find `a/b` In the binomial expansion `(a-b)^n, nge5` the sum of 5th and 6th terms is zero. Then find `a/b`
In the binomial expansion `(a-b)^n, nge5` the sum of 5th and 6th terms is zero. Then find `a/b` In the binomial expansion `(a-b)^n, nge5` the sum of 5th and 6th terms is zero. Then find `a/b`
In the binomial expansion of (a-b)^n, n ≥ 5, the sum of the 5 th and 6 th terms is zero. The a / ... In the binomial expansion of (a-b)^n, n ≥ 5, the sum of the 5 th and 6 th terms is zero. The a / ...
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In the binomial expansion of (a - b)^n , nGE5 m the sum of the 5th and 6th terms is zero m then a/b= In the binomial expansion of (a - b)^n , nGE5 m the sum of the 5th and 6th terms is zero m then a/b=
In the binomial expansion of \\(\\left( a - b \\right)^{n},\\ n \\geq 5\\),the sum of 5th and 6t.... In the binomial expansion of \\(\\left( a - b \\right)^{n},\\ n \\geq 5\\),the sum of 5th and 6t....
23 - The Binomial Theorem & Binomial Expansion - Part 1 23 - The Binomial Theorem & Binomial Expansion - Part 1
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