Prove that the acute angle between two diagonals of a cube is `cos^-1(1/3)`

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XII Vectors Show that the angle between two diagonals of a cube is cos^-1(1/3) . XII Vectors Show that the angle between two diagonals of a cube is cos^-1(1/3) .
Angle between two diagonal of cube,or ∅=cos-¹(1/3) Angle between two diagonal of cube,or ∅=cos-¹(1/3)
Show that the angle between any two diagonals of a cube is `cos^(-1)((1)/(3))`. Show that the angle between any two diagonals of a cube is `cos^(-1)((1)/(3))`.
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Show that the angle between two diagonals of a cube is cos^(-1)(1/3)dot | CLASS 12 | SCALAR OR D... Show that the angle between two diagonals of a cube is cos^(-1)(1/3)dot | CLASS 12 | SCALAR OR D...
Angle between two diagonals of a cube is Cos theta = 1/3 | Product of Vectors @EAG Angle between two diagonals of a cube is Cos theta = 1/3 | Product of Vectors @EAG
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Show that d angle b/w the any two diagonals of a cube is Cos inverse 1/3 @EAG Show that d angle b/w the any two diagonals of a cube is Cos inverse 1/3 @EAG