In the given figure , D is a point on the side BC of `Delta ABC` such that `angle ADC=angle BAC`. .

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13 D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB. In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.
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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA2 = CB.CD || Maths D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA2 = CB.CD || Maths
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In the adjoining figure, in DeltaABC, point D is on side BC such that, angleBAC = angleADC. Prov... In the adjoining figure, in DeltaABC, point D is on side BC such that, angleBAC = angleADC. Prov...
D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY] D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY]