If `int_(0)^(pi)x f(sin x) dx = a int_(0)^(pi)f (sin x) dx`, then a =

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If `int_(0)^(pi) x f (sin x) dx = A int _(0)^(pi//2) f(sin x) dx ,` then A is equal to If `int_(0)^(pi) x f (sin x) dx = A int _(0)^(pi//2) f(sin x) dx ,` then A is equal to
If ∫_0^π▒〖xf(sin⁡x)〗 dx=A∫_0^(π/2)▒〖f(sin⁡x)〗 dx then A is | Math Master | Impetus Gurukul If ∫_0^π▒〖xf(sin⁡x)〗 dx=A∫_0^(π/2)▒〖f(sin⁡x)〗 dx then A is | Math Master | Impetus Gurukul
int0​ to π xf(sinx)dx #integration #iitjam#12th #jeeadvance #importantquestions @M.K.Classes1311   int0​ to π xf(sinx)dx #integration #iitjam#12th #jeeadvance #importantquestions @M.K.Classes1311  
If `int_(0)^(pi)xf(sinx)dx=A int_(0)^(pi//2) f(sinx)dx`, then A is If `int_(0)^(pi)xf(sinx)dx=A int_(0)^(pi//2) f(sinx)dx`, then A is
If int_0^pi x f(sinx) dx=A int_0^(pi/2) f(sinx)dx, then A is(A) pi/2(B) pi(C) 0(D) 2pi | 12 | DE... If int_0^pi x f(sinx) dx=A int_0^(pi/2) f(sinx)dx, then A is(A) pi/2(B) pi(C) 0(D) 2pi | 12 | DE...
Calculus Help: If f is continuous on [0, π], use the substitution u=π-x to show that ∫ xf(sinx)dx = Calculus Help: If f is continuous on [0, π], use the substitution u=π-x to show that ∫ xf(sinx)dx =
If `int_0^(pi)xf(sinx)dx=Aint_0^(pi/2)f(sinx)dx`, then A is If `int_0^(pi)xf(sinx)dx=Aint_0^(pi/2)f(sinx)dx`, then A is
If `int_0^pi x f(sinx) dx=A int_0^(pi/2) f(sinx)dx`, then `A` is (A) `pi/2` (B) `pi` (C) `0` (D) `2p If `int_0^pi x f(sinx) dx=A int_0^(pi/2) f(sinx)dx`, then `A` is (A) `pi/2` (B) `pi` (C) `0` (D) `2p