Given ` P(A cup B)=0.6 , P(A capB)=0.2` , then probability of exactly one of the event occurs is

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Calculating P(A^c \cup B^c) Given Conditional Probabilities | UPSC ISS 2024 Paper-1 | Problem-31 Calculating P(A^c \cup B^c) Given Conditional Probabilities | UPSC ISS 2024 Paper-1 | Problem-31
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