prove that (aI+bE)^3=a^3I+3a^2bE , where a and b are arbitrary scalars #B.sc1styear

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SAQ video 5 || Show that (aI+bE)³=a³I+3a²bE where I is the unit matrix of order 2 SAQ video 5 || Show that (aI+bE)³=a³I+3a²bE where I is the unit matrix of order 2
if `A=[[0,1],[0,0]]` then show that `(aI+bA)^3=a^3I+3a^2bA.` if `A=[[0,1],[0,0]]` then show that `(aI+bA)^3=a^3I+3a^2bA.`
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