How to show that: 1+(tanθ)^2=(secθ)^2, 1+(cotθ)^2=(cosecθ)^2 and (secθ)^2+(cosecθ)^2=(cotθ+tanθ)^2

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Trigonometry : Table -2 Trigonometry : Table -2
Prove that : (sinθ+cosecθ)^2 + (cosθ+secθ)^2 = 7+tan^2 θ+cot^2 θ. Prove that : (sinθ+cosecθ)^2 + (cosθ+secθ)^2 = 7+tan^2 θ+cot^2 θ.
Prove that : (1+cotθ-cosecθ)(1+tanθ+secθ) = 2 ...|| Class 10 || rd question || Prove that : (1+cotθ-cosecθ)(1+tanθ+secθ) = 2 ...|| Class 10 || rd question ||
Prove that cot θ + tan θ = sec θ cosec θ /trigonometry identify proof Prove that cot θ + tan θ = sec θ cosec θ /trigonometry identify proof
Prove the Identity: (tan θ)/(sec θ - 1) + (tan θ)/(sec θ + 1) = 2 cosec θ | Trigonometry Question Prove the Identity: (tan θ)/(sec θ - 1) + (tan θ)/(sec θ + 1) = 2 cosec θ | Trigonometry Question
Prove the following that : tan^3θ/1+tan^2θ + cot^3θ/1+cot^2θ = secθcosecθ-2sinθcosθ...|| Class 10 || Prove the following that : tan^3θ/1+tan^2θ + cot^3θ/1+cot^2θ = secθcosecθ-2sinθcosθ...|| Class 10 ||
Prove that : √{sec^2(θ) + cosec^2(θ)} = tanθ + cotθ ...|| Class 10 || Prove that : √{sec^2(θ) + cosec^2(θ)} = tanθ + cotθ ...|| Class 10 ||
(Cosecθ - Sinθ)(Secθ - Cosθ)(tanθ + cotθ) is equal to (Cosecθ - Sinθ)(Secθ - Cosθ)(tanθ + cotθ) is equal to