If f(x) =log(1+ ax) - log(1 -bx) /x, x≠0 & k,x = 0 and f (x) is continuous at x = 0, then the value

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Let y(x) = (1+x) (1+x2)(1+x4)(1+x8)(1+x16). Then y Let y(x) = (1+x) (1+x2)(1+x4)(1+x8)(1+x16). Then y' - y" at x = -1 = is