D is point on side BC of triangle ABC such Angle ADC = Angle BAC I Show that CA^2 = CB.CD #shorts

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13 D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA^2 = CB.CD. D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA^2 = CB.CD.
D is a point on the side BC of a 🔺 ABC such that angle ADC =angle BAC, prove that CA²=CB. CD#pyq D is a point on the side BC of a 🔺 ABC such that angle ADC =angle BAC, prove that CA²=CB. CD#pyq
D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC . D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC .
D is a point on the side BC of a triangle ABC such that ∟ADC=∟BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that ∟ADC=∟BAC. Show that CA²=CB.CD.
D is a point on the side B C of a triangle ABC such that ∠ADC=∠BAC. Show that CA^2=CB·CD. D is a point on the side B C of a triangle ABC such that ∠ADC=∠BAC. Show that CA^2=CB·CD.
D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD. D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD