The resistance R=V/I where V=(200 + 5)V and I=(20 +0.2)A. percentage error in measurement of R ,JEE

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The resistance R=V/I where V= 200± 5 V and I = 20± 0.2 A , the percentage error in the | English The resistance R=V/I where V= 200± 5 V and I = 20± 0.2 A , the percentage error in the | English
The resistance R=V/I where V=(200 ± 5)V and I=(20 ± 0.2)A, the percentage error in the measurement The resistance R=V/I where V=(200 ± 5)V and I=(20 ± 0.2)A, the percentage error in the measurement
The resistance R = V/I where V = (200±5) volt and I= (20±0.2)A the percentage error.. | jee physics The resistance R = V/I where V = (200±5) volt and I= (20±0.2)A the percentage error.. | jee physics
The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage
The resistance R = V/I where V = ( 100 +- 5)V and I = (10 +- 0.2 )A. Find the percentage error in R The resistance R = V/I where V = ( 100 +- 5)V and I = (10 +- 0.2 )A. Find the percentage error in R
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If voltage V = (100 ± 5) V and current I = (10 ± 0.2) A, the percentage error in resistance R is : If voltage V = (100 ± 5) V and current I = (10 ± 0.2) A, the percentage error in resistance R is :
The resistance R= V/I where V= (50±2) volt and I= (20±0.2) A . The percentage error in R is x%... The resistance R= V/I where V= (50±2) volt and I= (20±0.2) A . The percentage error in R is x%...