a² - 11ab + b² = 0 হয় তাহলে দেখাও যে, log(a-b)/3= ½(log a + log b)

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Class-9, Maths.(logarithm)/a^2-11ab+b^2=0 হলে প্রমাণ করো যে,log (a-b)/3=1/2(log a+log b). Class-9, Maths.(logarithm)/a^2-11ab+b^2=0 হলে প্রমাণ করো যে,log (a-b)/3=1/2(log a+log b).
Logarithm solved example | if log [(a-b)/5] = 1/2[log a + log b] | P.T. : a^2 + b^2 = 27ab | Logarithm solved example | if log [(a-b)/5] = 1/2[log a + log b] | P.T. : a^2 + b^2 = 27ab |
If `a^(2)+b^(2)=23ab`, then prove that `log(a+b)/5=1/2(loga+logb)` If `a^(2)+b^(2)=23ab`, then prove that `log(a+b)/5=1/2(loga+logb)`
provelog ⅓(a+b) =½(loga +log b).Given a²+b²=7ab provelog ⅓(a+b) =½(loga +log b).Given a²+b²=7ab
If log (a+b/3) = log a + log b/2 find a/b + b/a If log (a+b/3) = log a + log b/2 find a/b + b/a
log(a+b)+log(a-b)-log(a^2-b^2) || log(a+b)+log(a-b)-log(a^(2)-b^(2))= #iitfoundationseries log(a+b)+log(a-b)-log(a^2-b^2) || log(a+b)+log(a-b)-log(a^(2)-b^(2))= #iitfoundationseries
यदि loga+b/3=1/2(loga+logb) है तो सिद्ध किजिए कि a^2+b^2=7ab यदि loga+b/3=1/2(loga+logb) है तो सिद्ध किजिए कि a^2+b^2=7ab
log(AB)=logA+logB PROOF log(AB)=logA+logB PROOF