Electric field in the given figure is directed along + X direction and given by E_x=5Ax+2B,

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Electric field in Fig. is directed along \( +X \) direction and given by \( E_{X}=5 A x+2 ~ B \)... Electric field in Fig. is directed along \( +X \) direction and given by \( E_{X}=5 A x+2 ~ B \)...
In Fig, electric field is dirceted along `+X` direction and is given by `E_(x) = 5 Ax + 2 B`, where In Fig, electric field is dirceted along `+X` direction and is given by `E_(x) = 5 Ax + 2 B`, where
The electric field components in Fig. 1.88 are Ex = a x1/2, Ey = Ez = 0, in which a = 800 N / Cm2. The electric field components in Fig. 1.88 are Ex = a x1/2, Ey = Ez = 0, in which a = 800 N / Cm2.
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