Q26 The sum of all the real roots of the equation(e^2x-4)(6e^2x-5e^x+1)=0 isJEE Main 2022 (Online)

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The sum of all the real roots of the equation (e^2x − 4)(6e^2x − 5e^x +1) = 0 is The sum of all the real roots of the equation (e^2x − 4)(6e^2x − 5e^x +1) = 0 is
The sum of all the real roots of the equation (e^2x-4)(6e^2x-5e^x+1)=0 is The sum of all the real roots of the equation (e^2x-4)(6e^2x-5e^x+1)=0 is
The sum of all real roots of equation (e^2x-4)(6e^2x-5e^x+1)=0| JEE MAIN 2022 MATHS PYQ SOLUTION The sum of all real roots of equation (e^2x-4)(6e^2x-5e^x+1)=0| JEE MAIN 2022 MATHS PYQ SOLUTION
The sum of all the real roots of the equation (e^2x −4)(6e^2x −5e^x +1)=0 The sum of all the real roots of the equation (e^2x −4)(6e^2x −5e^x +1)=0
The sum of all the real roots of the equation (e^(2x)-4)(6e^(2x)-5e^(x)+1)=0 is | CLASS 12 | JE... The sum of all the real roots of the equation (e^(2x)-4)(6e^(2x)-5e^(x)+1)=0 is | CLASS 12 | JE...
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how is e^e^x=1 solvable?? how is e^e^x=1 solvable??
JEE-main 2022:- 24 June shift-2 Math paper Question 2 solution | #jeemain2022 #projecteducation JEE-main 2022:- 24 June shift-2 Math paper Question 2 solution | #jeemain2022 #projecteducation