PQR is a right angled triangle, where `/_P = 90` PD is perpendicular to QR. Then `(PQ)/sqrt(PR)...

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(W) \( P Q R \) is a right angled triangle, where \( \angle P= \) \( 90^{\circ} . \overline{P D}... (W) \( P Q R \) is a right angled triangle, where \( \angle P= \) \( 90^{\circ} . \overline{P D}...
In a right angled triangle PQR, ∠PRQ = 90°.Draw the perpendicular bisector of PR and QR. In a right angled triangle PQR, ∠PRQ = 90°.Draw the perpendicular bisector of PR and QR.
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