prove (1+tan^2 A/1+cot^2 A)=(1-tanA/1-cotA)^2=tan^2A ||class 10 exercise 8.4 Question 5 ka x part

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Prove (1+tan^2 A)/(1+cot^2 A)=((1-tanA)/(1-cotA))^2=tan^2 A| Ex 8.4 Q5 (x) Prove (1+tan^2 A)/(1+cot^2 A)=((1-tanA)/(1-cotA))^2=tan^2 A| Ex 8.4 Q5 (x)
Class - 10 Ex - 8.4, Q-1,2,3,4,5 (Trigonometry) NCERT CBSE Class - 10 Ex - 8.4, Q-1,2,3,4,5 (Trigonometry) NCERT CBSE
1+Tan2A/1+Cot2A=(1-TanA/1-CotA)2=Tan2A 1+Tan2A/1+Cot2A=(1-TanA/1-CotA)2=Tan2A
10th.. (1+tan^2 A/1+cot^2 A)=(1-tanA/1-cotA)^2=tan^2A introduction to trigonometry EX. 8.4 Q.NO. 5 10th.. (1+tan^2 A/1+cot^2 A)=(1-tanA/1-cotA)^2=tan^2A introduction to trigonometry EX. 8.4 Q.NO. 5
Ex. 8.4 (Q.5) {i,ii} Chapter:8 Introduction To Trigonometry | Ncert Maths Class 10 | Cbse. Ex. 8.4 (Q.5) {i,ii} Chapter:8 Introduction To Trigonometry | Ncert Maths Class 10 | Cbse.
NCERT Class 10 Maths Exercise 8.4 Q-5(x) #(1+tan^2A/1+Cot^2A) =(1-tanA/1-cotA)^2=Tan^2A# Ex 8.4 Q 5 NCERT Class 10 Maths Exercise 8.4 Q-5(x) #(1+tan^2A/1+Cot^2A) =(1-tanA/1-cotA)^2=Tan^2A# Ex 8.4 Q 5
Prove that 1 plus tan square a divide by 1 plus cot square a is equal to 1 minus tan a divide by 1 Prove that 1 plus tan square a divide by 1 plus cot square a is equal to 1 minus tan a divide by 1
Q90 | Prove that (1+tan^2⁡θ)/(1+cot^2⁡θ)=((1-tan⁡θ)/(1-cot⁡θ))^2 | 1 + tan square theta by 1 + cot Q90 | Prove that (1+tan^2⁡θ)/(1+cot^2⁡θ)=((1-tan⁡θ)/(1-cot⁡θ))^2 | 1 + tan square theta by 1 + cot