Show that integration of 0 to pi/2 sin^2x/sinx+cosx dx =1/root2 log(root2+1) #IIT JEE,

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Show that ∫(xβ†’0,Ο€/2)sin2x/(sinx + cosx) = (1/√2)log ( √2+1) Integration 12th Important Question Show that ∫(xβ†’0,Ο€/2)sin2x/(sinx + cosx) = (1/√2)log ( √2+1) Integration 12th Important Question
πŸ”₯ POV: Integration - Look at me! πŸ‘€ πŸ’ͺ | JEE 2024 | Math | Bhoomika Ma πŸ”₯ POV: Integration - Look at me! πŸ‘€ πŸ’ͺ | JEE 2024 | Math | Bhoomika Ma'am
show that Integral 0 to Ο€/2 sinΒ²x/sinx+cosx dx = 1/√2 log (√2+1) show that Integral 0 to Ο€/2 sinΒ²x/sinx+cosx dx = 1/√2 log (√2+1)
`int_0^(pi/2) cos^2x/(sinx+cosx)dx=1/sqrt2(log(sqrt2+1))` `int_0^(pi/2) cos^2x/(sinx+cosx)dx=1/sqrt2(log(sqrt2+1))`
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This chapter closes now, for the next one to begin. πŸ₯‚βœ¨.#iitbombay #convocation This chapter closes now, for the next one to begin. πŸ₯‚βœ¨.#iitbombay #convocation
integral 0 to (pi/2) (sinx-cosx)/(1+sinxcosx) dx || `int_(0)^((pi)/(2))(sinx-cosx)/(1+sinxcosx)dx` integral 0 to (pi/2) (sinx-cosx)/(1+sinxcosx) dx || `int_(0)^((pi)/(2))(sinx-cosx)/(1+sinxcosx)dx`