In figure, QR/QS=QT/PR and angle 1 = angle 2 . Show that triangle PQS similar to triangleTQR.

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In figure, QR/QS = QT/PR and ∠ 1 = ∠ 2 Show that Δ PQS ~ Δ TQR | Q4 Exercise 6 3 class 10 In figure, QR/QS = QT/PR and ∠ 1 = ∠ 2 Show that Δ PQS ~ Δ TQR | Q4 Exercise 6 3 class 10
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Triangles Class 10. In the figure, QR /QS = QT/PR and ∠1 = ∠ 2 then prove that ∆PQS ~ ∆TQR Triangles Class 10. In the figure, QR /QS = QT/PR and ∠1 = ∠ 2 then prove that ∆PQS ~ ∆TQR
in fig QR/QS= QT/PR AND angle 1= angle 2 show that ∆PQS~∆TQR. similar triangles 10th CBSE..ex 6.3 in fig QR/QS= QT/PR AND angle 1= angle 2 show that ∆PQS~∆TQR. similar triangles 10th CBSE..ex 6.3
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Ex6.3QNo4. QR/QS = QT/PR and angle1=angle2 show that ΔPQS~ΔTQR. class 10 Ex6.3QNo4. QR/QS = QT/PR and angle1=angle2 show that ΔPQS~ΔTQR. class 10
In Figure. QR/QS=QT/PR  and ∠1=∠2. Show that △PQS∼△TQR. In Figure. QR/QS=QT/PR  and ∠1=∠2. Show that △PQS∼△TQR.
in figure, QR/QS= QT/PR and angle 1= angle 2 .Show that triangle PQS is similar to triangle TQR in figure, QR/QS= QT/PR and angle 1= angle 2 .Show that triangle PQS is similar to triangle TQR