Let A and B be square matrix of the same order. Does (A + B)^2 = A^2 + 2AB + B^2 hold ? If not, why?

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If A and B are two square matrices of the same order, then (A + B)^2 = A^2 + AB + BA + B^2. Also whe If A and B are two square matrices of the same order, then (A + B)^2 = A^2 + AB + BA + B^2. Also whe
If A and B are nn matrices, then (A-B)^2 =A^2-2AB+B^2 | Plainmath If A and B are nn matrices, then (A-B)^2 =A^2-2AB+B^2 | Plainmath
If A and B are square matrices of the same order, explain, why in general (A -B)^2 ≠ A^2 - 2AB + B^2 If A and B are square matrices of the same order, explain, why in general (A -B)^2 ≠ A^2 - 2AB + B^2
If A and B are square matrices of the same order, explain, why in general (A +B)^2 ≠ A^2 + 2AB + B^2 If A and B are square matrices of the same order, explain, why in general (A +B)^2 ≠ A^2 + 2AB + B^2
proof// (a-b)^2= a^2-2ab+b^2 // proof// (a-b)^2= a^2-2ab+b^2 //
If A and B are square matrices of the same order such that AB=BA, then show that (A+B)^2=A^2+2AB+B^2 If A and B are square matrices of the same order such that AB=BA, then show that (A+B)^2=A^2+2AB+B^2
Let A and B be square matrices of the other 3×3. Is (AB)^2 = A^2 B^2 ? Give reasons. Let A and B be square matrices of the other 3×3. Is (AB)^2 = A^2 B^2 ? Give reasons.
If A and B are square matrices of the same order then `(A+B)^2=A^2+2AB+B^2` implies (A) `AB=0 If A and B are square matrices of the same order then `(A+B)^2=A^2+2AB+B^2` implies (A) `AB=0