In a cyclic quadrilateral A B C D, if (∠ B-∠ D)=60^∘, show that the smaller of the two is 60^∘.

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In a cyclic quadrilateral A B C D, if ∠ A-∠ C=60^∘, prove that the smaller of two is 60^∘ In a cyclic quadrilateral A B C D, if ∠ A-∠ C=60^∘, prove that the smaller of two is 60^∘
In a cyclic quadrilateral ABCD, if angle A - angle C = 60°, prove that the smaller of two is 60°. In a cyclic quadrilateral ABCD, if angle A - angle C = 60°, prove that the smaller of two is 60°.
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In a circle, ABCD is a cyclic quadrilateral in which AE is drawn parallel to CD, and BA is produced In a circle, ABCD is a cyclic quadrilateral in which AE is drawn parallel to CD, and BA is produced
Challenge 60: Cosine and Cyclic Quadrilateral Challenge 60: Cosine and Cyclic Quadrilateral
The diagram shows cyclic quadrilateral ABCD. BDandAC intersect at X.Angle BAD=74° and angle BCA=34° The diagram shows cyclic quadrilateral ABCD. BDandAC intersect at X.Angle BAD=74° and angle BCA=34°
Solution 60: Varignon, Brahmagupta, Ptolemy, and Cyclic Quadrilateral Solution 60: Varignon, Brahmagupta, Ptolemy, and Cyclic Quadrilateral
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