Indefinite Integral #Solution of questions Asked in NIMCET 2008 to 2018 Lecture By Nitin Agrawal

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The value of \[\int {\frac{{(x + 1)}}{{x(x{e^x} + 1)}}dx} \] is equal to [NIMCET 2014] The value of \[\int {\frac{{(x + 1)}}{{x(x{e^x} + 1)}}dx} \] is equal to [NIMCET 2014]
Definite Integral Revision Class for NIMCET 2021 Part 1 by Nitin Agrawal | INPS Classes | Definite Integral Revision Class for NIMCET 2021 Part 1 by Nitin Agrawal | INPS Classes |
If \[\int {{{\sec }^2}x\cos e{c^4}xdx = - \frac{1}{3}{{\cot }^3}x + k\tan x - 2\cot x + C} \], the If \[\int {{{\sec }^2}x\cos e{c^4}xdx = - \frac{1}{3}{{\cot }^3}x + k\tan x - 2\cot x + C} \], the
\[\int {f(x)dx = g(x)} {\rm{ then }}\int {{x^5}f({x^3})dx} \] [NIMCET 2023] \[\int {f(x)dx = g(x)} {\rm{ then }}\int {{x^5}f({x^3})dx} \] [NIMCET 2023]
The value of \[\int {\frac{{\left( {{x^2} - 1} \right)dx}}{{{x^3}\sqrt {2{x^4} - 2{x^2} + 1} }}} \] The value of \[\int {\frac{{\left( {{x^2} - 1} \right)dx}}{{{x^3}\sqrt {2{x^4} - 2{x^2} + 1} }}} \]