show that integral of 0 to 1 log(1+x)/1+x² dx =π/2 log2 by skydhoni

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Show that Integral 0 to 1 log(1+x)/(1+x^2) dx =π/2 log2 | Integration of log(1+x)/(1+x^2) dx Show that Integral 0 to 1 log(1+x)/(1+x^2) dx =π/2 log2 | Integration of log(1+x)/(1+x^2) dx
Show that Integral 0 to infinity log(1+x)/(1+x^2) dx =π/2 log2 | Integration of log(1+x)/(1+x^2) dx Show that Integral 0 to infinity log(1+x)/(1+x^2) dx =π/2 log2 | Integration of log(1+x)/(1+x^2) dx
Show that ∫0, π/2[]log (x+1/x) dx/1+x^2=-πlog2 Show that ∫0, π/2[]log (x+1/x) dx/1+x^2=-πlog2
7#DefiniteIntegration Integral 0 to 1 Log [(1 + x) by 1 + x²] dx 7#DefiniteIntegration Integral 0 to 1 Log [(1 + x) by 1 + x²] dx
Evaluate int 0 to 1 log(1+x)/(1+x²)dx | integrate log(1+x)/(1+x^2) from 0 to 1 #cbsepyqs Evaluate int 0 to 1 log(1+x)/(1+x²)dx | integrate log(1+x)/(1+x^2) from 0 to 1 #cbsepyqs
Show that Integral 0 to ♾️ log (x+1/x)/(1+x^2) dx =π/2 log2 | Integration of log (x+1/x)/(1+x²) dx Show that Integral 0 to ♾️ log (x+1/x)/(1+x^2) dx =π/2 log2 | Integration of log (x+1/x)/(1+x²) dx
∫_0^1log (1+x)/(1+x^2) d x=π/8(log 2) ∫_0^1log (1+x)/(1+x^2) d x=π/8(log 2)
Definite Integration LAQ 7 | log(1+x)/1+x^2 #maths2b #definiteintegration #inter2ndyear Definite Integration LAQ 7 | log(1+x)/1+x^2 #maths2b #definiteintegration #inter2ndyear