If a, b, c, are in A.P, then the determinant `|[x+2,x+3,x+2a],[x+3,x+4, | Class 12 Maths | Doubtnut

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If a,b,c are in A.P., then the determinant br `|[x+2, x+3, x+2a],[x+3,x | Class 12 Maths | Doubtnut If a,b,c are in A.P., then the determinant br `|[x+2, x+3, x+2a],[x+3,x | Class 12 Maths | Doubtnut
if a,b,c are in A P then the determinant x+2 x+3 x+2a , x+3 x+4 x+2b , x+4 x+5 x+2c is if a,b,c are in A P then the determinant x+2 x+3 x+2a , x+3 x+4 x+2b , x+4 x+5 x+2c is
If a, b, c, are in A.P, then the determinant `|x+2x+3x+2a x+3x+4x+2b x+4x+5x+2c|` is (A) 0 (B) 1... If a, b, c, are in A.P, then the determinant `|x+2x+3x+2a x+3x+4x+2b x+4x+5x+2c|` is (A) 0 (B) 1...
If `a,b,c` ,are in `A.P,` then the determinant , `|(x+2,x+3,x+2a),(x+3,x+4,x+2b),(x+4,x+5,x+2c... If `a,b,c` ,are in `A.P,` then the determinant , `|(x+2,x+3,x+2a),(x+3,x+4,x+2b),(x+4,x+5,x+2c...
If a,b,c are in AP show that `|[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0` If a,b,c are in AP show that `|[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0`
Inverse of a Matrix Inverse of a Matrix
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