If f(x)= integration from 0 to 2 e^|x-t| dt , then the minimum value of f(x) =(JEE Mains 2023)

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JEE Main 2023 The minimum values of the function 𝒇(𝒙)=∫_𝟎^𝟐 𝒆^|𝒙−𝒕| 𝒅t is JEE Main 2023 The minimum values of the function 𝒇(𝒙)=∫_𝟎^𝟐 𝒆^|𝒙−𝒕| 𝒅t is
The minimum value of the function f(x) = ∫0 2e|x-1| dt is _________ The minimum value of the function f(x) = ∫0 2e|x-1| dt is _________
JEE Main 2023 𝒇(𝒙)+∫_𝟎^𝒙〖𝒇(𝒕)√(𝟏−(𝐥𝐧 𝒇(𝒕))^𝟐 ) 𝒅𝒕〗=𝒆 ∀𝒙∈[𝟎,𝝅/𝟐] then (𝟔 𝐥𝐧𝒇(𝝅/𝟔))^𝟐 is equal to JEE Main 2023 𝒇(𝒙)+∫_𝟎^𝒙〖𝒇(𝒕)√(𝟏−(𝐥𝐧 𝒇(𝒕))^𝟐 ) 𝒅𝒕〗=𝒆 ∀𝒙∈[𝟎,𝝅/𝟐] then (𝟔 𝐥𝐧𝒇(𝝅/𝟔))^𝟐 is equal to
Q) If Integration ∫ (−0.15) to 0.15  |100𝑥^2−1| 𝑑𝑥 =𝑘/3000, then 𝑘 is #jee #jeemains #jee Q) If Integration ∫ (−0.15) to 0.15  |100𝑥^2−1| 𝑑𝑥 =𝑘/3000, then 𝑘 is #jee #jeemains #jee
Q) The value of(𝑒^(𝜋/4)+∫ 0^(𝜋/4)  𝑒^(−𝑥) tan^50 𝑥𝑑𝑥)/(∫ 0^(𝑑𝑥) 𝑒^(−𝑒^) (−𝑒^49+15) 𝑥)𝑑𝑥 Q) The value of(𝑒^(𝜋/4)+∫ 0^(𝜋/4)  𝑒^(−𝑥) tan^50 𝑥𝑑𝑥)/(∫ 0^(𝑑𝑥) 𝑒^(−𝑒^) (−𝑒^49+15) 𝑥)𝑑𝑥
Respect for IIT Bombay 📉📉📉 | IIT Status #jee2025 #iitbombay #iit Respect for IIT Bombay 📉📉📉 | IIT Status #jee2025 #iitbombay #iit
Tricky Question of JEE Main 2023 | 98% Failed to solve this #shorts #jee #jee2023 #jeemains Tricky Question of JEE Main 2023 | 98% Failed to solve this #shorts #jee #jee2023 #jeemains
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