(a-b)=3 (b-c)=5 (c-a)=1 find (a³+b³+c³-3abc)/(a+b+c)

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if a - b= 3 b-c=5 c -a= 1 then the value of (a³+b³+c³-3abc)/(a+b+c) if a - b= 3 b-c=5 c -a= 1 then the value of (a³+b³+c³-3abc)/(a+b+c)
a³+b³=? , a³-b³=? a³+b³=? , a³-b³=?
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(a + b + c)^3 | maths formula (a + b + c)^3 | maths formula
(a+b)³=? , (a-b)³=? (a+b)³=? , (a-b)³=?
prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca ) prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca )
If a + b + c = 5 and ab+bc+ca=10, then prove thata^3+b^3+c^3-3abc=-25 If a + b + c = 5 and ab+bc+ca=10, then prove thata^3+b^3+c^3-3abc=-25