Finding point on the parabola 𝑦^2=8𝑥 which is at minimum distance from the circle 𝑥^2+(𝑦+6)^2=1 are

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Shortest distance: Point on parabola y^2=8x which is at a minimum distance from circle x^2+(y+6)^2=1 Shortest distance: Point on parabola y^2=8x which is at a minimum distance from circle x^2+(y+6)^2=1
"The coordinates of a point on the parabola `y^2=8x` whose distance from the circle `x^2+(y+6)^2=1` "The coordinates of a point on the parabola `y^2=8x` whose distance from the circle `x^2+(y+6)^2=1`
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The coordinates of a point on the parabola y^2=8 x whose distance from the circle x^2+(y+6)^2=1 i... The coordinates of a point on the parabola y^2=8 x whose distance from the circle x^2+(y+6)^2=1 i...
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Let , Pbe the point on the parabola y^(2) = 8x which is at a minimum distance from the centre Co... Let , Pbe the point on the parabola y^(2) = 8x which is at a minimum distance from the centre Co...
The coordinates of a point on the parabola `y^2=8x` whose distance from the circle `x^2+(y+6)^2... The coordinates of a point on the parabola `y^2=8x` whose distance from the circle `x^2+(y+6)^2...