if A O B is a diameter of the circle and A C=B C, then ∠ C A B is equal to

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In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to:(A) 30º (B) 60º In Fig.10.5, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to:(A) 30º (B) 60º
If AOB is a diameter of the circle andAC=BC, then angle CAB is equal to | 9 | CIRCLES | MATHS ... If AOB is a diameter of the circle andAC=BC, then angle CAB is equal to | 9 | CIRCLES | MATHS ...
In figure, if AOB is a diameter of the circle and AC=BC, then `angle CAB` is equal to In figure, if AOB is a diameter of the circle and AC=BC, then `angle CAB` is equal to
if AOB is a diameter of the circle and AC= BC, then ∠CAB is equal to: (A) 30^∘ (B) 60^∘ (C) 90^∘ ... if AOB is a diameter of the circle and AC= BC, then ∠CAB is equal to: (A) 30^∘ (B) 60^∘ (C) 90^∘ ...
In the given figure, if AOB is a diameter of the circle and AC=BC, the ∠CAB is equal .... In the given figure, if AOB is a diameter of the circle and AC=BC, the ∠CAB is equal ....
In the given figure, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to :(a) 30° In the given figure, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to :(a) 30°
In the given figure, AOB is a diameter and DC is parallel to AB. If CAB = x, find in terms of x. In the given figure, AOB is a diameter and DC is parallel to AB. If CAB = x, find in terms of x.
Class 10 | Circles | EX 17(A) | Question 16 | AOB is a diameter | angle CAB = 0 | Concisemathematics Class 10 | Circles | EX 17(A) | Question 16 | AOB is a diameter | angle CAB = 0 | Concisemathematics