gcd (a,b) × lcm (a,b)= a.b (proof) || Number Theory

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the RELATIONSHIP between LEAST COMMON MULTIPLE and GREATEST COMMON DIVISOR the RELATIONSHIP between LEAST COMMON MULTIPLE and GREATEST COMMON DIVISOR
Proof : a × b = GCD(a,b) × LCM(a,b) Proof : a × b = GCD(a,b) × LCM(a,b)
It It's So Elegant! 😍 Prove gcd(a,b)*lcm(a,b)=a*b with the GCD is a Linear Combination Theorem
let let a and b be positive integers then (a,b)[a,b]=ab. or gcd (a,b) lcm (a,b) =ab |Great vision| let let a and b be positive integers then (a,b)[a,b]=ab. or gcd (a,b) lcm (a,b) =ab |Great vision|
Number Theory | Common Multiple || Least Common Multiple ||Theorem: gcd(a,b).lcm(a,b)=a.b| Topic 2.4 Number Theory | Common Multiple || Least Common Multiple ||Theorem: gcd(a,b).lcm(a,b)=a.b| Topic 2.4
a.b = gcd(a, b). lcm(a, b) a.b = gcd(a, b). lcm(a, b)
gcd(a,b) x lcm(a,b) = a x b gcd(a,b) x lcm(a,b) = a x b
gcd(a,b)*lcm(a,b)=ab . gcd(a,b)*lcm(a,b)=ab .