Q) Let 𝑝=lim(π‘₯β†’0^+ )β€Š(1+tan^2 √π‘₯)^(1/2π‘₯) then log 𝑝 #jee #maths #jee2025 #limits #jee2026 #jee

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Q) lim x = 0 { tan( pie/4 + x ) } ^1/x #maths #jee2025 #jeeadvance #jeemain #jeeaspirants #iit Q) lim x = 0 { tan( pie/4 + x ) } ^1/x #maths #jee2025 #jeeadvance #jeemain #jeeaspirants #iit
Q) If 𝛼=lim_(π‘₯β†’0^+ )β€Š((𝑒^√tanπ‘₯βˆ’π‘’^√π‘₯)/(√tanπ‘₯βˆ’βˆšπ‘₯)) and 𝛽=lim_(π‘₯β†’0)β€Š(1+sinπ‘₯)^(1/2 cotπ‘₯) are the roots Q) If 𝛼=lim_(π‘₯β†’0^+ )β€Š((𝑒^√tanπ‘₯βˆ’π‘’^√π‘₯)/(√tanπ‘₯βˆ’βˆšπ‘₯)) and 𝛽=lim_(π‘₯β†’0)β€Š(1+sinπ‘₯)^(1/2 cotπ‘₯) are the roots
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Q) lim(π‘›β†’βˆž)β€Š[1/(1+𝑛)+1/(2+𝑛)+1/(3+𝑛)+…+1/2𝑛] is equal to #jee #maths #jeeproblems #jee2026 #maths Q) lim(π‘›β†’βˆž)β€Š[1/(1+𝑛)+1/(2+𝑛)+1/(3+𝑛)+…+1/2𝑛] is equal to #jee #maths #jeeproblems #jee2026 #maths