If A= {x: x^2-5x+6=0}, B ={2,4}, C ={4,5} then Ax(BnC) is/sets and relations/nta/jee mains/2020/

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If `A={x:x^(2)-5x+6=0},B={2,4},C={4,5}` then find `Axx(BnnC)` If `A={x:x^(2)-5x+6=0},B={2,4},C={4,5}` then find `Axx(BnnC)`
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