Let an element a of group G be of an odd order, then show that there exist b in G such that b^2=a.

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If G is abelian and has odd order then the product over G equals the identity If G is abelian and has odd order then the product over G equals the identity
let G be a group & x be an element of odd order in G then for any element y in G their exist y^2=x let G be a group & x be an element of odd order in G then for any element y in G their exist y^2=x
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