alpha and beta are distinct roots of the equation x^2-(t^2-5t+6)x+1=0, an=alpha^n+beta^n. Then..

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\[\alpha ,\beta \] be distinct root \[{x^2} - \left( {{t^2} - 5t + 6} \right)x + 1 = 0,t \in R\] \[\alpha ,\beta \] be distinct root \[{x^2} - \left( {{t^2} - 5t + 6} \right)x + 1 = 0,t \in R\]
alpha and beta roots of quadratic equation | Finding new equation alpha and beta roots of quadratic equation | Finding new equation
Let a, ẞ be the distinct roots of the equation x ^ 2 - (t ^ 2 - 5t + 6) * x + 1 = 0 t ∈ R and | JEE Let a, ẞ be the distinct roots of the equation x ^ 2 - (t ^ 2 - 5t + 6) * x + 1 = 0 t ∈ R and | JEE
Let alpha and beta be the roots of the equations,5x^2+6x-2=0.If Sn =(alpha)^n + (beta)^n , n=1,2,3.. Let alpha and beta be the roots of the equations,5x^2+6x-2=0.If Sn =(alpha)^n + (beta)^n , n=1,2,3..
let α, β be the distinct roots of the equation x²-(t²-5t+6)x+1=0,t ∈ R & aₙ=αⁿ+βⁿ then minimum value let α, β be the distinct roots of the equation x²-(t²-5t+6)x+1=0,t ∈ R & aₙ=αⁿ+βⁿ then minimum value
How to derive formulas of the roots of Quadratic Equations How to derive formulas of the roots of Quadratic Equations
Let α, β be the distinct roots of the quadratic equation x^2 - (t^2 - 5t + 6)x + 1= 0,a_n = α^n + β^ Let α, β be the distinct roots of the quadratic equation x^2 - (t^2 - 5t + 6)x + 1= 0,a_n = α^n + β^
If alpha and beta roots of the equation 5x^2+6x-2=0 .If S_n=(alpha)^n+(beta)^n ,n=1,2,3.. then If alpha and beta roots of the equation 5x^2+6x-2=0 .If S_n=(alpha)^n+(beta)^n ,n=1,2,3.. then