If cos (α+β)=0, then sin (α-β) can be reduced to (a) cosβ (b) cos 2 β (c) sinα (d) sin 2 α PI

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If cos (α+β)=0, then sin (α-β) can be reduced to (A) cosβ (B) cos 2 β (C) sinα (D) sin 2 α (W) If cos (α+β)=0, then sin (α-β) can be reduced to (A) cosβ (B) cos 2 β (C) sinα (D) sin 2 α (W)
5 If cos α + β = 0, then sin α – β can be reduced to 5 If cos α + β = 0, then sin α – β can be reduced to
if cos alpha + cosbeta+cosgamma=0=sinalpha+sinbeta+singamma then cos^2alpha+cos^2beta+cos^2gamma=3/2 if cos alpha + cosbeta+cosgamma=0=sinalpha+sinbeta+singamma then cos^2alpha+cos^2beta+cos^2gamma=3/2
Show cos(a-b)cos(a+b) = cos^2 a - sin^2 b. Sum and Difference Identity Show cos(a-b)cos(a+b) = cos^2 a - sin^2 b. Sum and Difference Identity
6#IfCosA+CosB+CosC=0=SinA+SinB+SinC then Cos^2(A)+Cos^2(B)+Cos^2(C)=3/2=Sin^2(A)+Sin^2(B)+Sin^2(C) 6#IfCosA+CosB+CosC=0=SinA+SinB+SinC then Cos^2(A)+Cos^2(B)+Cos^2(C)=3/2=Sin^2(A)+Sin^2(B)+Sin^2(C)
If Cos(a+b) =0, then Find Sin(a-b)=? If Cos(a+b) =0, then Find Sin(a-b)=?
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DeMoivre DeMoivre's theorem|Complex number|cos⁡α+cos⁡β+cos⁡γ=0=sin⁡α+sin⁡β+sin⁡γ |TS AP INTER mathematics 2A