Solution of elementary number theory by David M.Burton| If gcd(a,35)=1,then show that a^12≡1(mod35)

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If gcd(a,35)=1 Show that a^12=1(mod35).If gcd(a,42)=1 Show that 168=3.7.8 divides a^6-1. If gcd(a,35)=1 Show that a^12=1(mod35).If gcd(a,42)=1 Show that 168=3.7.8 divides a^6-1.
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