Proof of integral of Sec x = log | sec x + tan x | + c = log | tan ( π/4 + x/2) | + c

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∫ sec x dx = ln |sec x + tan x| + C or ∫ sec x dx = ln | tan [ (x/2) + (π/4) ] | + C. ∫ sec x dx = ln |sec x + tan x| + C or ∫ sec x dx = ln | tan [ (x/2) + (π/4) ] | + C.
Integral of sec X into log (sec x + tan x) Integral of sec X into log (sec x + tan x)
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