sec(π/2-x)=cosecx solve || sec(π/2-θ)

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How to show that sec(π/2-θ)=cosecθ, cosec(π/2-θ)=secθ and cot(π/2-θ)=tanθ geometrically How to show that sec(π/2-θ)=cosecθ, cosec(π/2-θ)=secθ and cot(π/2-θ)=tanθ geometrically
sec ( π/2 - θ ) = cosec θ || Urdu sec ( π/2 - θ ) = cosec θ || Urdu
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cosec ( π/2 - θ ) = sec θ || Urdu cosec ( π/2 - θ ) = sec θ || Urdu
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