E(aX+bY)=aE(X)+bE(Y) for X,Y discrete - Proof part 1 of 3

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E(aX+bY)=aE(X)+bE(Y) for X,Y discrete - Proof part 3 of 3 E(aX+bY)=aE(X)+bE(Y) for X,Y discrete - Proof part 3 of 3
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#15-1 E(aX+b)= aE(X)+b proof for X discrete part 1 of 2 #15-1 E(aX+b)= aE(X)+b proof for X discrete part 1 of 2
#15-2 E(aX+b)= aE(X)+b proof for X discrete part 2 of 2 #15-2 E(aX+b)= aE(X)+b proof for X discrete part 2 of 2
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E(Y)=aE(x) +b and V(Y) =a^2V(Y) where Y=aX+b / problems on continues random variables E(Y)=aE(x) +b and V(Y) =a^2V(Y) where Y=aX+b / problems on continues random variables
For any constant a and b, E[aX+b]=aE[X]+b and E[aX-b]=aE[X]-b (Discrete) For any constant a and b, E[aX+b]=aE[X]+b and E[aX-b]=aE[X]-b (Discrete)
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