The sum of the series `sum_(r=1)^n (-1)^(r-1)*nC_r(a-r)` is equal to :

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If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n` If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n`