The difference between maximum and minimum value of the expression y=1+2 sin x+3 cos ^2 x is(A) 1...

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y = 2sin(x) - 1 - cos²(x). Find the minimum and maximum value of y without using calculus. y = 2sin(x) - 1 - cos²(x). Find the minimum and maximum value of y without using calculus.
Given that `y=(10)/(sinx+sqrt(3)cosx)`.Minimum value of y is Given that `y=(10)/(sinx+sqrt(3)cosx)`.Minimum value of y is
This is a very famous limit This is a very famous limit
Maximum value of f(x)=sin x+cos x is (a) 1 (b) 2 (c) 1/√(2) (d) √(2) Maximum value of f(x)=sin x+cos x is (a) 1 (b) 2 (c) 1/√(2) (d) √(2)
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