Two Δ's BAC & BDC, right angled at A and D If AC and DB intersect at p. Prove that AP×PC=DP×AB

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Two triangles BAC & BDC right angled at A and D respectively, are drawn on the same base, BC & on Two triangles BAC & BDC right angled at A and D respectively, are drawn on the same base, BC & on
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