If A+B+C=π&cos A=cos B. cos C then tan B. tanC has the value equal to: (A) 1 (B) 1 / 2 (C) 2

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If A+B+C =π and cosA = cosB.cosC, prove that: tanA = tanB + tanC. If A+B+C =π and cosA = cosB.cosC, prove that: tanA = tanB + tanC.
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