neet 2025 to find acceleration of particle using t=x^2+x relation #neet2025

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In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = x In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = x
NEET 2025: (By 2 methods)In some appropriate units, time (t) and position (x) relation of a moving p NEET 2025: (By 2 methods)In some appropriate units, time (t) and position (x) relation of a moving p
In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = In some appropriate units, time (t) and position (x) relation of a moving particle is given by t =
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FIND ACCELERATION t= ax^2+bx where a,b are constant, t=time , x=distance FIND ACCELERATION t= ax^2+bx where a,b are constant, t=time , x=distance
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