In the adjoining figure, AB || DC. CE and DE bisects ∠BCD and ∠ADC respectively. Prove that AB = AD

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In the adjoining figure, AB || DC. CE and DE bisects ∠BCD and ∠ADC respectively. Prove that AB = In the adjoining figure, AB || DC. CE and DE bisects ∠BCD and ∠ADC respectively. Prove that AB =
In the adjoining figure, `AD = DC` and bisects `angleADC`. Prove that `DeltaADB cong DeltaCDB`. In the adjoining figure, `AD = DC` and bisects `angleADC`. Prove that `DeltaADB cong DeltaCDB`.
In the given figure, AE bisects ∠CAD and ∠B = ∠C. Prove that AE||BC. In the given figure, AE bisects ∠CAD and ∠B = ∠C. Prove that AE||BC.
In the adjoining figure, it is given that CE || BA, angle BAC = 80° and angle ECD = 35°. Find.... In the adjoining figure, it is given that CE || BA, angle BAC = 80° and angle ECD = 35°. Find....
In Figure, /_B C D=/_A D C\\ a n d\\ /_A C B=/_B D Adot\nProve that A D=B C\\ a n d\\ /_A=/_B | ... In Figure, /_B C D=/_A D C\\ a n d\\ /_A C B=/_B D Adot\nProve that A D=B C\\ a n d\\ /_A=/_B | ...
Topper Vs Back bencher | Exterior Angle Property #shorts #youtubeshorts #ashortaday #viralmaths #fun Topper Vs Back bencher | Exterior Angle Property #shorts #youtubeshorts #ashortaday #viralmaths #fun
In the adjoining fig., BD and CD are angle bisectors of exterior ∠B and exterior ∠C of ∆ABC In the adjoining fig., BD and CD are angle bisectors of exterior ∠B and exterior ∠C of ∆ABC
In Fig. the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO In Fig. the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO