Given ,log2=0.301 and log3=0.477, then the number of digits before decimal in `3^12times2^8`is

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Given, log 2=0.301 and log 3=0.477, then the number of digits before decimal in 3^12× 2^8 is (a) ... Given, log 2=0.301 and log 3=0.477, then the number of digits before decimal in 3^12× 2^8 is (a) ...
If `log2=0.301 and log3=0.477`, find the number of digits in: `(3^15xx2^10)` If `log2=0.301 and log3=0.477`, find the number of digits in: `(3^15xx2^10)`
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