If a²+b²+49c²+18=2(b-28c-a), then find the value of (a+b-7c) |Important Question| Competitive Exams

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If a ^ 2 + b ^ 2 + 49c ^ 2 + 18 = 2(b + 28c - a) then the value of (2a - b + 7c) is: If a ^ 2 + b ^ 2 + 49c ^ 2 + 18 = 2(b + 28c - a) then the value of (2a - b + 7c) is:
If a 2 + b2 + 49C2 + 18 = 2(b – 28c – a) then the value of (a + b - 7c) is: If a 2 + b2 + 49C2 + 18 = 2(b – 28c – a) then the value of (a + b - 7c) is:
If a^2 + b^2 + 49c^2 + 18 = 2(b – 28c – a) then the value of (a + b – 7c) is: If a^2 + b^2 + 49c^2 + 18 = 2(b – 28c – a) then the value of (a + b – 7c) is:
ID634- If a^2 + b^2 + 49c^2 + 18 = 2(b + 28c – a), then the value of (2a – b + 7c) is ? ID634- If a^2 + b^2 + 49c^2 + 18 = 2(b + 28c – a), then the value of (2a – b + 7c) is ?
If a^2 + b^2 + 49c^2 + 18 = 2(b – 28c – a), then the value of (a – b – 7c) is: If a^2 + b^2 + 49c^2 + 18 = 2(b – 28c – a), then the value of (a – b – 7c) is:
SSC CHSL PAST YEAR QUESTION | VITORR CLASSES | If a^2 + 4b^2 + 49c^2 + 18 = 2(2b + 28c – a) SSC CHSL PAST YEAR QUESTION | VITORR CLASSES | If a^2 + 4b^2 + 49c^2 + 18 = 2(2b + 28c – a)
How a2 - b2= (a+b)(a-b) ? #maths #algebra #formula How a2 - b2= (a+b)(a-b) ? #maths #algebra #formula
If a²+b²=52, a-b=2, find ab If a²+b²=52, a-b=2, find ab