If A+B+C=pi then prove that : sin2A+sin2B+sin2C=4sinAsinBsinC

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Theorem 1 :If `A+B+C=pi` then prove that `sin2A+sin2B+sin2C=4sinAsinBsinC` Theorem 1 :If `A+B+C=pi` then prove that `sin2A+sin2B+sin2C=4sinAsinBsinC`
Theorem 1 :If `A+B+C=pi` then prove that `sin2A+sin2B+sin2C=4sinAsinBsinC` Theorem 1 :If `A+B+C=pi` then prove that `sin2A+sin2B+sin2C=4sinAsinBsinC`
If A + B + C = 180, Prove that sin2A + sin2B + sin2C = 4 sinA sinB sinC If A + B + C = 180, Prove that sin2A + sin2B + sin2C = 4 sinA sinB sinC
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यदि A+B+C=pi हो तो सिद्ध कीजिए कि - sin2A+sin2B+sin2C=4sinAsinBsinC | 12 | त्रिकोणमितीय सर्वसमि... यदि A+B+C=pi हो तो सिद्ध कीजिए कि - sin2A+sin2B+sin2C=4sinAsinBsinC | 12 | त्रिकोणमितीय सर्वसमि...
Proof related to triangles.**sin2A+sin2B+sin2c=4sinAsinBsinC Proof related to triangles.**sin2A+sin2B+sin2c=4sinAsinBsinC