a+b+c=6, a²+b²+c²=14, ab+bc+ca=? | (a+b+c)²=? | (a+b+c)² formula | Algebraic Identity | Square

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If a+b+c=6 and a²+b²+c²=14, then what is the value of (a-b)²+(b-c)²+(c-a)² ? If a+b+c=6 and a²+b²+c²=14, then what is the value of (a-b)²+(b-c)²+(c-a)² ?
if a + b + c = 6 and (a² + b² + c² )= 14 then (a b + BC + CA) = if a + b + c = 6 and (a² + b² + c² )= 14 then (a b + BC + CA) =
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If a + b + c = 6 and a² + b²+c² = 14, then what is the value of (a - b)2 + (b-c)²+(c-a)²? If a + b + c = 6 and a² + b²+c² = 14, then what is the value of (a - b)2 + (b-c)²+(c-a)²?
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