Let X be any point on the side BC of a △ ABC. If XM, XN are drawn parallel to BA and CA meeting CA,

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P is any point on side BC of ABC. PQ || BA and PR || CQ are drawn. RQ is extended to meet BC P is any point on side BC of ABC. PQ || BA and PR || CQ are drawn. RQ is extended to meet BC
X is any point on side BC of ▲ABC.XM,XN are || BA,CA. Line MN meets line CB at T. Prove TX² = TB.TC X is any point on side BC of ▲ABC.XM,XN are || BA,CA. Line MN meets line CB at T. Prove TX² = TB.TC
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