if p is the perpendicular distance from origin to line x/a+y/b=1 then show that (1/p^2)=1/a^2+1/b^2.

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If p and be the distances of origin from the lines and , then Perpendicular Distance If p and be the distances of origin from the lines and , then Perpendicular Distance
reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin
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if p is the length of perpendicular from origin to line x/a+y/b=1 then prove 1/(a^2)+1/(b^2)=1/(p^2) if p is the length of perpendicular from origin to line x/a+y/b=1 then prove 1/(a^2)+1/(b^2)=1/(p^2)
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If the perpendicular distance of the line (x/a)+(y/b)=1 from the origin is `p//sqrt(2)` show that If the perpendicular distance of the line (x/a)+(y/b)=1 from the origin is `p//sqrt(2)` show that