Integral of e^(tan^(-1)x)/(1+x²) || Integration by substitution

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∫▒e^(〖tan〗^(-1) x) ((1+x+x²)/(1+x²))dx is equal to xe^(〖tan〗^(-1) x)+ c b) x2e^(〖tan〗^(-1) x)+ c ∫▒e^(〖tan〗^(-1) x) ((1+x+x²)/(1+x²))dx is equal to xe^(〖tan〗^(-1) x)+ c b) x2e^(〖tan〗^(-1) x)+ c
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