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Download lagu UP TGT-21:Find Positive integer n for [(1+i)/(1-i)]^n = 1,for any iota (i). secara gratis hanya untuk keperluan promosi. Dukung artis favorit kamu dengan membeli musik original di iTunes atau platform resmi lainnya.
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![[ ( 1 + i ) / (1 - i ) ]^n = 1 ; n = ?](https://i.ytimg.com/vi/3_BqZzSwsy8/hqdefault.jpg?sqp=-oaymwEjCOADEI4CSFryq4qpAxUIARUAAAAAGAElAADIQj0AgKJDeAE=&rs=AOn4CLDjPVEoHE71wsSuplEXMloBoTN1OA)
[ ( 1 + i ) / (1 - i ) ]^n = 1 ; n = ?
What is the smallest positive integer n for which (1+i)^2n=(1-i)^2n .....?
(n−1)! + 1 = n² for integers n ≥ 0 | #dogmathic | #numbertheory | #discretemath
![The smallest positive integer n for which [(1+i)/(1-i)]^n =1 is (a) 2 (b) 3 (c) 4 (d) 6 #complex](https://i.ytimg.com/vi/sodsCF4Bp9o/hq720.jpg?sqp=-oaymwE9COgCEMoBSFryq4qpAy8IARUAAAAAGAAlAADIQj0AgKJDeAHwAQH4AbYIgAKAD4oCDAgAEAEYfyA5KDUwDw==&rs=AOn4CLACVVmF_ITaXwIojuCl_A-2vDkYRg)
The smallest positive integer n for which [(1+i)/(1-i)]^n =1 is (a) 2 (b) 3 (c) 4 (d) 6 #complex
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